How to create new python file with increament number, if doesn't exist?

[Avnesh Shakya]

Thanks


On Mon, May 27, 2013 at 4:19 PM, Denis McMahon <denismfmcmahon at gmail.com>wrote:

> On Mon, 27 May 2013 02:27:59 -0700, Avnesh Shakya wrote:
>
> > I want to create a new python file like 'data0.0.5', but if it is
> > already exist then it should create 'data0.0.6', if it's also exist
> > then next like 'data0.0.7'. I have done, but with range, please give
> > me suggestion so that I can do it with specifying range.
>
> Try and put your description into the sequence of instructions you want
> the computer follow.
>
> For this problem, my sequence of instructions would be:
>
> 1) Find the highest numbered existing file that matches the filename
> data0.0.[number]
>
> 2) Create a new file that is one number higher.
>
> Now the solution is easy. Find the list of filenames in the directory
> that match a suitable regular expression, take the numeric value of a
> substring of the filename for each file and find the highest, add one to
> it, then create the new file name.
>
> Something like the following (untested) with the relevant imports etc:
>
> nfn="data0.0."+str(max([int(f[8:])for f in os.listdir(p)if re.match
> ('^data0.0.[0-9]+$',f)])+1)
>
> --
> Denis McMahon, denismfmcmahon at gmail.com
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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