list comprehension misbehaving
Wolfgang Maier
wolfgang.maier at biologie.uni-freiburg.de
Thu Mar 28 11:52:29 EDT 2013
Tim Chase <python.list <at> tim.thechases.com> writes:
> it's because you're taking a snapshot copy of "a" in the middle of
> the loop. In your first example, if you change it to
>
> results = []
> for i in a[:-1]:
> results.append(a.pop() and a)
> print results
>
> you get the same thing as your list comprehension because each item
> in "results" refers to the now-(mostly)empty "a".
>
> -tkc
>
>
Hi Tim, and thanks a lot for helping!
I got it:
in the comprehension case I'm only getting my results at the end,
when my list has been emptied!
Thanks, I got stuck with this, but now it's obvious.
Best,
Wolfgang
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