Altering 2 statements from Python 2.6 => 3.2

[Νίκος Γκρ33κ]

Τη Πέμπτη, 28 Μαρτίου 2013 4:28:04 π.μ. UTC+2, ο χρήστης Chris Angelico έγραψε:
> On Thu, Mar 28, 2013 at 1:16 PM, Νίκος Γκρ33κ <nikos.gr33k at gmail.com> wrote:
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> > Τη Πέμπτη, 28 Μαρτίου 2013 12:55:11 π.μ. UTC+2, ο χρήστης Chris Angelico έγραψε:
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> >> On Thu, Mar 28, 2013 at 7:18 AM, Νίκος Γκρ33κ <nikos.gr33k at gmail.com> wrote:
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> >> > date = date.strftime('%A, %e %b %Y').decode('cp1253').encode('utf8')
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> >> For a start, figure out what you're trying to do. I'm trying to get my
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> >> head around this line and I'm not getting anywhere. Is 'date' an
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> >> instance of datetime.date()? And whatever it is, why do you then
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> >> immediately rebind it? And why decode an arbitrary string using an
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> >> arbitrary encoding? And why.... never mind. Start here:
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> >> http://www.joelonsoftware.com/articles/Unicode.html
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> >> One of Python 3's big features is that it forces you to distinguish
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> >> text strings from binary ones.
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> >> ChrisA
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> > I had to use it like that in order for date to be appear correctly in greek otherwise it would seem like chinese.
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> > So now you mena i dont have to decode anym ore and use it liek that?
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> > date = date.strftime('%A, %e %b %Y').encode('utf8')
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> I mena, or mean, that you have to figure out what you're doing before
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> you try to figure out how to do it.
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> Or if you want help, then try providing context, like what data type 'date' is.

I'am just tryign to print the date with proper greek letters as it uses to work with Python v2.6

date gets calculated here:

date = ( datetime.utcnow() + timedelta(hours=2) ).strftime( '%y-%m-%d %H:%M:%S' )

I'am not sure but i believe that the decode must be taken out in python 3.x because objexts returned in unicoide now, but i'am not sure.