At a loss on python scoping.

[Shiyao Ma]

After read Dave's answer, I think I confused LEGB with attribute lookup.
So, a.r has nothing to do with LEGB.

On Tue, Mar 26, 2013 at 7:03 PM, Shiyao Ma <i at introo.me> wrote:

> Thx, really a nice and detailed explanation.
>
>
> On Tue, Mar 26, 2013 at 6:07 PM, Dave Angel <davea at davea.name> wrote:
>
>> On 03/26/2013 02:17 AM, Shiyao Ma wrote:
>>
>>> Hi,
>>> suppose I have a file like this:
>>> class A:
>>>      r = 5
>>>      def func(self, s):
>>>          self.s = s
>>> a = A()
>>> print(a.r)    # this should print 5, but where does py store the name of
>>> r
>>>
>>> a.func(3)
>>> print(a.s)    # this should print 3, also where does py store this name.
>>> what's the underlying difference between the above example?
>>>
>>>
>> I don't think this is a scoping question at all.  These references are
>> fully qualified, so scoping doesn't enter in.
>>
>> The class A has a dictionary containing the names of r and func.  These
>> are class attributes.  Each instance has a dictionary which will contain
>> the name s AFTER the A.func() is called.  Ideally such an attribute will be
>> assigned in the __init__() method, in which case every instance will have s
>> in its dictionary.
>>
>> When you use a.qqq  the attribute qqq is searched for in the instance
>> dictionary and, if not found, in the class dictionary.  If still not found,
>> in the parent classes' dictionary(s).
>>
>> You can use dir(A) and dir(a) to look at these dictionaries, but it shows
>> you the combination of them, so it's not as clear.  In other words, dir(a)
>> shows you both dictionaries, merged.  (Seems to me dir also sometimes
>> censors some of the names, but that's a vague memory. It's never left out
>> anything I cared about, so maybe it's things like single-underscore names,
>> or maybe just a poor memory.)
>>
>>
>> --
>> DaveA
>> --
>> http://mail.python.org/**mailman/listinfo/python-list<http://mail.python.org/mailman/listinfo/python-list>
>>
>
>
>
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