iterating over a list as if it were a circular list

Sven svenito at gmail.com
Thu Mar 7 04:27:42 EST 2013


Stupid keyboard shortcuts, sent it too early. Apologies


I was wondering what the best approach for the following might be.

Say you have a list P of points and another list N of other items. You can
always assume that

len(N) <= len(P)

Now I would like to iterate over P and place one N at each point. However
if you run out of N I'd like to restart from N[0] and carry on until all
the points have been populated.
So far I've got (pseudo code)

i = 0
for point in points:
    put N[i] at point
    if i > len(N):
        i = 0

is this the most pythonic way to accomplish this?

Additionally, what if I wanted to pull a random element from N, but I want
to ensure all elements from N have been used before starting to pick
already chosen random elements again.
So far I thought of duplicating the list and removing the randomly chosen
elements from the list, and when it's empty, re-copying it. But that seems
a little "wrong" if you know what I mean.

-- 
./Sven
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://mail.python.org/pipermail/python-list/attachments/20130307/b38c0dab/attachment.html>


More information about the Python-list mailing list