Question on for loop

[Bryan Devaney]

On Monday, March 4, 2013 4:37:11 PM UTC, Ian wrote:
> On Mon, Mar 4, 2013 at 7:34 AM, Bryan Devaney <bryan.devaney at gmail.com> wrote:
> 
> >>         if character not in lettersGuessed:
> 
> >>
> 
> >>         return True
> 
> >>
> 
> >> return False
> 
> >
> 
> > assuming a function is being used to pass each letter of the letters guessed inside a loop itself that only continues checking if true is returned, then that could work.
> 
> >
> 
> > It is however more work than is needed.
> 
> >
> 
> > If you made secretword a list,you could just
> 
> >
> 
> > set(secretword)&set(lettersguessed)
> 
> >
> 
> > and check the result is equal to secretword.
> 
> 
> 
> Check the result is equal to set(secretword), I think you mean.
> 
> 
> 
> set(secretword).issubset(set(lettersguessed))
> 
> 
> 
> might be slightly more efficient, since it would not need to build and
> 
> return an intersection set.
> 
> 
> 
> One might also just do:
> 
> 
> 
> all(letter in lettersguessed for letter in secretword)
> 
> 
> 
> Which will be efficient if lettersguessed is already a set.

You are correct. sorry for the misleading answer, was digging through old shell scripts all day yesterday and brain was obviously not not the better for it.