class factory question
Peter Otten
__peter__ at web.de
Wed Jun 26 10:46:55 EDT 2013
Tim wrote:
> I am not completely understanding the type function I guess. Here is an
> example from the interpreter:
>
> In [1]: class MyClass(object):
> ...: pass
> ...:
> In [2]: type('Vspace', (MyClass,), {})
> Out[2]: __main__.Vspace
> In [3]: x = Vspace()
>
---------------------------------------------------------------------------
> NameError Traceback (most recent call
> last) C:\Python27\Scripts\<ipython-input-3-a82f21420bf3> in <module>()
> ----> 1 x = Vspace()
>
> NameError: name 'Vspace' is not defined
No, you are not understanding how Python namespaces work ;)
To get a Vspace in the global namespace you'd have to bind that name
Vspace = type(...)
which defeats your plan of mass creation of such names. The clean way to
cope with the situation is to use a dict:
classnames = ["Vspace", ...]
classes = {name: type(name, ...) for name in classnames}
Then you can access the Vspace class with
classes["Vspace"]
If that is inconvenient for your usecase you can alternatively update the
global (module) namespace:
globals().update((name, type(name, ...) for name in classnames)
For example:
>>> class A(object): pass
...
>>> globals().update((n, type(n, (A,), {})) for n in ["Beta", "Gamma"])
>>> Beta
<class '__main__.Beta'>
>>> issubclass(Beta, A)
True
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