A certainl part of an if() structure never gets executed.

[Ferrous Cranus]

On 16/6/2013 3:04 μμ, R. Michael Weylandt wrote:
> On Sun, Jun 16, 2013 at 12:06 PM, Ferrous Cranus <support at superhost.gr> wrote:
>
> I appreciate you've returned to your Ferrous Cranus persona for this
> interchange. It reminds me not to get hung up on concerns of
> futility...
>
>> On 16/6/2013 1:42 μμ, R. Michael Weylandt wrote:
>>>>
>>>
>>> ## CODE SNIPPET##
>>> a = 552315251254
>>> b = a
>>> c =  552315251254
>>>
>>> a is b # True _on my machine_
 >
 > And this pattern continues for any sort of Python object.
 >>> a is c # False _on my machine_

And in mine is also True.


 >>> id(a)
140160465571760
 >>> id(b)
140160465571760
 >>> id(c)
140160465571696

Since all object result to point to actual number 6 why don't all of 
them (a,b,c) bound to the same memory address.

a and b seem both objects of the same identity, which means they are 
both bound to the same memory address(140160465571760)

how come c's memory address is different than a's and b's ?
After all, this is the 3rd object pointing to number 6.

And why not d and e and f and g are all objects of the same memory address?


> In fact, b does not go "through" a. The memory address referenced
> exists even if the "a" binding is removed using "del a" or some other
> mechanism. Imagine this scenario:
>
> [a]
>      \
>       6
>     /
> [b]
>
> Using the name "a" or "b" simply tells Python where to look for a
> value, but the value itself is not associated with "a" or "b".

If i understood you correctly, you say:

unbounded memory address = value of 6

a = pointer to memory address that holds 6
b = pointer to memory address that holds 6

So, a and b, are two objects(two variable names if you want) that are 
bounded to the same memory address. And their value is the address of 
unbounded memory address.
Correct?

>> what id() does, never heard of that function before.
>>
>
> It seems you've also never heard of Python's "help" function?
>
> Try
>
> help(id)
>
> at your interactive prompt and see what happens.

No i had no idea thagt was a bult-in help() function.
So id() is actually the memory address of an object which uniquely 
identifies it.


-- 
What is now proved was at first only imagined!