Split a list into two parts based on a filter?

[Serhiy Storchaka]

11.06.13 07:11, Roy Smith написав(ла):
> In article <mailman.2992.1370904643.3114.python-list at python.org>,
>   Roel Schroeven <roel at roelschroeven.net> wrote:
>
>> new_songs, old_songs = [], []
>> [(new_songs if s.is_new() else old_songs).append(s) for s in songs]
>
> Thanks kind of neat, thanks.
>
> I'm trying to figure out what list gets created and discarded.  I think
> it's [None] * len(songs).

It is the same as your klunky code, but consumes more memory.