[os.path.join(r'E:\Python', name) for name in []] returns []

[iMath]

在 2013年1月29日星期二UTC+8下午9时33分26秒，Steven D'Aprano写道：
> iMath wrote: > why [os.path.join(r'E:\Python', name) for name in []] returns [] ? Because you are iterating over an empty list, []. That list comprehension is the equivalent of: result = [] for name in []: result.append( os.path.join(r'E:\Python', name) ) Since you iterate over an empty list, the body of the loop never executes, and the result list remains empty. What did you expect it to do? -- Steven

just in order to get the full path name of each file .