Optimizing list processing

[Steven D'Aprano]

On Thu, 12 Dec 2013 00:59:42 +0000, MRAB wrote:

>> table = [(x, i) for i,x in enumerate(iterable)] 
>> table.sort()
> 
> This looks wrong to me:
> 
>> for x, i in table:
>>      table[i] = x

Yes, you're right, I over-simplified the example, and in doing so 
introduced a bug. What I actually use is:

for i, x in enumerate(table):
    table[i] = x[1]

modulo any further bugs introduced while copying and pasting :-)


-- 
Steven