List getting extended when assigned to itself
Steven D'Aprano
steve+comp.lang.python at pearwood.info
Sun Aug 25 01:31:48 EDT 2013
On Sun, 25 Aug 2013 09:22:27 +0530, Krishnan Shankar wrote:
> Hi Python Friends,
>
> I came across an example which is as below,
>
>>>> var = [1, 12, 123, 1234]
>>>> var
> [1, 12, 123, 1234]
>>>> var[:0]
> []
>>>> var[:0] = var
>>>> var
> [1, 12, 123, 1234, 1, 12, 123, 1234]
>>>>
>>>>
> Here in var[:0] = var we are assigning an entire list to the beginning
> of itself. So shouldn't it be something like,
>
> [[1, 12, 123, 1234], 1, 12, 123, 1234]
No, you have misunderstood how slicing works. When you assign to a slice,
you *replace* the existing slice with items from the other list:
py> L = [1, 2, 3, 4, 5]
py> L[2:4] = [None, None, None]
py> L
[1, 2, None, None, None, 5]
Notice that it does not insert the list [None, None, None] as a single
item.
If the slice you replace is empty, this is equivalent to inserting the
items:
py> L = [1, 2, 3, 4, 5]
py> L[2:2] = [None, None, None]
py> L
[1, 2, None, None, None, 3, 4, 5]
The beginning of the list is just an empty slice: L[:0] means "all the
items, starting at the beginning of the list, and finishing *before*
index zero". So that makes it an empty slice, and items are inserted
after the start of the list but before index zero:
py> L = [1, 2, 3, 4, 5]
py> L[:0] = [None, None, None]
py> L
[None, None, None, 1, 2, 3, 4, 5]
So assigning to a slice *always* extends. If you try to assign a single
value, not inside a list or other iterable, it fails:
py> L = [1, 2, 3, 4, 5]
py> L[:0] = None
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: can only assign an iterable
Remember that indexes in Python are *before* the item, so when slicing,
Python cuts at the vertical lines | as shown below:
| a | b | c | d | e | f | g |
The vertical lines are numbered 0 through 7, and the slice [2:5] cuts as
shown:
| a | b | c | d | e | f | g |
0---1---2---3---4---5---6---7
[2:5] => | c | d | e |
> It happens when we do the below,
>
>>>> var = [1, 12, 123, 1234]
>>>> var[0] = var
>>>> var
> [[...], 12, 123, 1234]
Here you are *not* assigning to a slice, but setting a single item. The
item at position 0 is replaced with the contents of var, which happens to
be the same list, but that is just a distraction. It is more clear when
you use a different value:
py> L = [1, 2, 3, 4, 5]
py> L[0] = "something"
py> L
['something', 2, 3, 4, 5]
> Literally var[0] = var and var[:0] = var almost meens the same.
No, they are very different.
Even though the difference is a single character, var[:index] and
var[index] are very different, no matter what the value of index. The
first is a slice ending at index, the second is a single item at index.
The same naturally applies to var[index:] as well, which is a slice
starting at index.
If you wish to insert a sequence as a single object, you have two
choices: you can use the list insert() method, or you can wrap the
sequence in a list, and then use slice assignment:
py> L = [1, 2, 3, 4, 5]
py> L[2:4] = [L]
py> L
[1, 2, [...], 5]
--
Steven
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