How to export a logging level?

[Jean-Michel Pichavant]

----- Original Message -----
> In my application I import a module and I want to set the same
> logging
> level
> as the main app to this module.
> 
> I've tried this code
> 
> main.py
> 
> import logging
> logger = logging.getLogger(__name__)
> lvl = logging.DEBUG
> LOG_FORMAT = "%(asctime)-6s %(levelname)s: %(name)s - %(message)s"
> logging.basicConfig(format=LOG_FORMAT, datefmt='%H:%M:%S', level=lvl)
> 
> from mymodule.myfile import MyClass
> 
> ...
>     def load_myclass(self):
>         lvl = logger.getEffectiveLevel()
>         mc = MyClass(self, lvl)
> 
> 
> myfile.py
> 
> import logging
> logger = logging.getLogger(__name__)
> 
> class MyClass(object):
>     def __init__(self, main, lvl):
>         logger.setLevel(lvl)
> 
> If I set the level to logging.DEBUG I can see all infos from the main
> but anything
> from my module.
> 
> Thanks for your advice.
> --
> Vincent V.V.
> Oqapy <https://launchpad.net/oqapy> . Qarte
> <https://launchpad.net/qarte> . PaQager
> <https://launchpad.net/paqager>
> --
> http://mail.python.org/mailman/listinfo/python-list
> 

Life is actually simpler, one rule to remember: you don't configure your loggers, ever. You let this worthless task to the user (in your case the main.py file or however import your module).

In myfile.py, the only logging related lines are:

import logging
logger = logging.getLogger(__name_)

Then you just log. How the logs  are processed, at which level, for which formatter, you don't care. The root logger will take care of that. Keep your main.py as it is and it should work.

JM