Function for examine content of directory

[Tigerstyle]

kl. 16:56:29 UTC+2 torsdag 6. september 2012 skrev Tigerstyle følgende:
> Hi guys,
> 
> 
> 
> I'm trying to write a module containing a function to examine the contents of the current working directory and print out a count of how many files have each extension (".txt", ".doc", etc.)
> 
>  
> 
> This is the code so far:
> 
> --
> 
> import os
> 
> 
> 
> path = "v:\\workspace\\Python2_Homework03\\src\\"
> 
> dirs = os.listdir( path )
> 
> filenames = {"this.txt", "that.txt", "the_other.txt","this.doc","that.doc","this.pdf","first.txt","that.pdf"}
> 
> extensions = []
> 
> for filename in filenames:
> 
>     f = open(filename, "w")
> 
>     f.write("Some text\n")
> 
>     f.close()
> 
>     name , ext = os.path.splitext(f.name)
> 
>     extensions.append(ext)
> 
> 
> 
> # This would print all the files and directories
> 
> for file in dirs:
> 
>     print(file)
> 
> 
> 
> for ext in extensions:
> 
>     print("Count for %s: " %ext, extensions.count(ext))
> 
>     
> 
> --
> 
> 
> 
> When I'm trying to get the module to print how many files each extension has, it prints the count of each ext multiple times for each extension type. Like this:
> 
> 
> 
> this.pdf
> 
> the_other.txt
> 
> this.doc
> 
> that.txt
> 
> this.txt
> 
> that.pdf
> 
> first.txt
> 
> that.doc
> 
> Count for .pdf:  2
> 
> Count for .txt:  4
> 
> Count for .doc:  2
> 
> Count for .txt:  4
> 
> Count for .txt:  4
> 
> Count for .pdf:  2
> 
> Count for .txt:  4
> 
> Count for .doc:  2
> 
> 
> 
> Any help is appreciated.
> 
> 
> 
> T