Function for examine content of directory

Tigerstyle laddosingh at gmail.com
Thu Sep 6 10:56:29 EDT 2012


Hi guys,

I'm trying to write a module containing a function to examine the contents of the current working directory and print out a count of how many files have each extension (".txt", ".doc", etc.)
 
This is the code so far:
--
import os

path = "v:\\workspace\\Python2_Homework03\\src\\"
dirs = os.listdir( path )
filenames = {"this.txt", "that.txt", "the_other.txt","this.doc","that.doc","this.pdf","first.txt","that.pdf"}
extensions = []
for filename in filenames:
    f = open(filename, "w")
    f.write("Some text\n")
    f.close()
    name , ext = os.path.splitext(f.name)
    extensions.append(ext)

# This would print all the files and directories
for file in dirs:
    print(file)

for ext in extensions:
    print("Count for %s: " %ext, extensions.count(ext))
    
--

When I'm trying to get the module to print how many files each extension has, it prints the count of each ext multiple times for each extension type. Like this:

this.pdf
the_other.txt
this.doc
that.txt
this.txt
that.pdf
first.txt
that.doc
Count for .pdf:  2
Count for .txt:  4
Count for .doc:  2
Count for .txt:  4
Count for .txt:  4
Count for .pdf:  2
Count for .txt:  4
Count for .doc:  2

Any help is appreciated.

T



More information about the Python-list mailing list