Script for finding words of any size that do NOT contain vowels with acute diacritic marks?

wxjmfauth at gmail.com wxjmfauth at gmail.com
Wed Oct 17 14:33:30 EDT 2012


Le mercredi 17 octobre 2012 20:28:21 UTC+2, Ian a écrit :
> On Wed, Oct 17, 2012 at 12:17 PM,  <wxjmfauth at gmail.com> wrote:
> 
> > Not at all, I knew this. In this I decided to program like
> 
> > this.
> 
> >
> 
> > Do you get it?  Yes/No  or True/False
> 
> 
> 
> It's just bad style, because both 'yes' and 'no' evaluate true.
> 
> 
> 
> if HasDiacritics('éléphant'):
> 
>     print('Correct!')
> 
> 
> 
> if HasDiacritics('elephant'):
> 
>     print('Error!')
> 
> 
> 
> Prints:
> 
> 
> 
> Correct!
> 
> Error!
> 
> 
> 
> You could replace the test with "if HasDiacritics('elephant') ==
> 
> 'yes':", but why force the caller to write that out when the former
> 
> test is more natural and less prone to error (e.g. typoing 'yes')?

I *know* all this. In my prev. msg, the goal was to emph. the
usage of *unicode.normalize()".

jmf



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