list comprehension question

[rusi]

On Oct 17, 7:37 pm, Dave Angel <d... at davea.name> wrote:

> And I'd wager all the improvement is in the inner loop, the dot() function.

Sorry -- red herring!

Changing

def mm1(a,b): return [[sum(x*y for x,y in zip(ra,rb)) for rb in
zip(*b)] for ra in a]

to

def mm1(a,b): return [[sum([x*y for x,y in zip(ra,rb)]) for rb in
zip(*b)] for ra in a]

makes the speed diff vanish