Question on Python Split

[subhabangalore at gmail.com]

On Monday, October 8, 2012 1:00:52 AM UTC+5:30, subhaba... at gmail.com wrote:
> Dear Group,
> 
> 
> 
> Suppose I have a string as, 
> 
> 
> 
> "Project Gutenberg has 36000 free ebooks for Kindle Android iPad iPhone."
> 
> 
> 
> I am terming it as,
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> 
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> str1= "Project Gutenberg has 36000 free ebooks for Kindle Android iPad iPhone." 
> 
> 
> 
> I am working now with a split function,
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> 
> 
> str_words=str1.split()
> 
> so, I would get the result as,
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> ['Project', 'Gutenberg', 'has', '36000', 'free', 'ebooks', 'for', 'Kindle', 'Android', 'iPad', 'iPhone.']
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> 
> 
> But I am looking for,
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> 
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> ['Project Gutenberg', 'has 36000', 'free ebooks', 'for Kindle', 'Android iPad', 'iPhone']
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> 
> 
> This can be done if we assign the string as,
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> 
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> str1= "Project Gutenberg, has 36000, free ebooks, for Kindle, Android iPad, iPhone,"
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> 
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> and then assign the split statement as,
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> str1_word=str1.split(",")
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> 
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> would produce,
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> ['Project Gutenberg', ' has 36000', ' free ebooks', ' for Kindle', ' Android iPad', ' iPhone', '']
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> 
> 
> My objective generally is achieved, but I want to convert each group here in tuple so that it can be embedded, like,
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> [(Project Gutenberg), (has 36000), (free ebooks), (for Kindle), ( Android iPad), (iPhone), '']
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> 
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> as I see if I assign it as
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> for i in str1_word:
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>        print i
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>        ti=tuple(i)
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>        print ti
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> 
> 
> I am not getting the desired result.
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> 
> 
> If I work again from tuple point, I get it as,
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> >>> tup1=('Project Gutenberg')
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> >>> tup2=('has 36000')
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> >>> tup3=('free ebooks')
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> >>> tup4=('for Kindle')
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> >>> tup5=('Android iPad')
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> >>> tup6=tup1+tup2+tup3+tup4+tup5
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> >>> print tup6
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> Project Gutenberghas 36000free ebooksfor KindleAndroid iPad
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> 
> 
> Then how may I achieve it? If any one of the learned members can kindly guide me.
> 
> Thanks in Advance,
> 
> Regards,
> 
> Subhabrata.
> 
> 
> 
> NB: Apology for some minor errors.

Thank you for nice answer. Your codes and discussions always inspire me.

Regards,
Subhabrata.