The type.__call__() method manages the calls to __new__ and __init__?
Marco
name.surname at gmail.com
Tue Nov 20 12:29:05 EST 2012
Looking at the documentation of Py3.3:
http://docs.python.org/3.3/reference/datamodel.html#object.__new__
I saw the method `__new__()` is called automatically when I create an
istance. After the call to __new__(), if it returns an instance `self`
then `self.__init__()` is called.
Because when I call an instance the __call__ method is called, and
because the classes are instances of type, I thought when I call a Foo
class this imply the call type.__call__(Foo), and so this one manages
the Foo.__new__ and Foo.__init__ calls:
>>> class Foo:
... def __new__(cls):
... print('Foo.__new__()')
... return super().__new__(cls)
... def __init__(self):
... print('Foo.__init__(self)')
...
>>> f = type.__call__(Foo)
Foo.__new__()
Foo.__init__(self)
Is that right? Thanks in advance
--
Marco
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