How to print python commands automatically?

[Peng Yu]

> Try with just --trace?
>
>
> C:\ramit>python.exe -m trace test.py
> C:\ramit\Python27\lib\trace.py: must specify one of --trace, --count, --report, --listfuncs, or --trackcalls
>
> C:\ramit>python -m trace --trace test.py
>  --- modulename: test, funcname: <module>
> test.py(2): def f():
> test.py(5): f()
>  --- modulename: test, funcname: f
> test.py(3):     print "Hello World!"
> Hello World!
>  --- modulename: trace, funcname: _unsettrace
> trace.py(80):         sys.settrace(None)

I have to explicitly specify the modules I want to ignore. Is there a
way to ignore all the modules by default?

~/linux/test/python/man/library/trace/import$ cat.sh main.py main.sh test.py
==> main.py <==
#!/usr/bin/env python

import test

test.test()


==> main.sh <==
#!/usr/bin/env bash

python -m trace --trace main.py


==> test.py <==
def test1():
  print "Hello World!"

def test():
  test1()

~/linux/test/python/man/library/trace/import$ python -m trace --trace
--ignore-module=test main.py
 --- modulename: main, funcname: <module>
main.py(3): import test
main.py(5): test.test()
Hello World!
 --- modulename: trace, funcname: _unsettrace
trace.py(80):         sys.settrace(None)


-- 
Regards,
Peng