Haskell -> Python

[Dave Angel]

On 11/02/2012 05:40 PM, Ian Kelly wrote:
> On Fri, Nov 2, 2012 at 1:19 PM,  <foster63 at gmail.com> wrote:
>> Is there anything anyone could recommend to make it more "Pythonic" or more functional.  It looks clumsy next to the Haskell.
> def options(heaps):
>     for i, heap in enumerate(heaps):
>         head = heaps[:i]
>         tail = heaps[i+1:]
>         yield from (head + [x] + tail for x in range(heap))
>
> "yield from" is Python 3.3 syntax.  If you're not using Python 3.3,
> then that line could be replaced by:
>
>         for x in range(heap):
>             yield head + [x] + tail
>
> Cheers,
> Ian
Perhaps range(heap) should be replaced by  range(len(heap))



-- 

DaveA