return respective values when mutiple keys are passed in dictionary

[Nikhil Verma]

Thanks Arnaud

List comprehension method  really works nicely.sorry for late reply.






On Mon, May 7, 2012 at 7:10 PM, Arnaud Delobelle <arnodel at gmail.com> wrote:

> On 7 May 2012 12:31, Nikhil Verma <varma.nikhil22 at gmail.com> wrote:
> > HI All
> >
> > I was clearing my concepts on dictionary and stuck in this problem.
> > I have a dictionary which i have formed by using zip function on two
> list so
> > that one list (which i have hardcoded) becomes the keys and the other
> list
> > becomes its values.
> >
> > Now i want to know how can i get the values of keys at once if i pass the
> > keys in a dictionary.
> >
> > Let say I have a dictionary
> >
> > mydict = {'a':'apple' , 'b':'boy' ,'c' : 'cat', 'd':'duck','e':'egg'}
> >
> > Now if i do :-
> >
> > mydict.get('a')
> > 'apple'
>
> mydict['a'] is the usual way to get the value associated with a key.
> The difference is that it will throw an exception if the key doesn't
> exist, which is most of the time the sanest thing to do.
>
> > What i want is some i pass keys in get and in return i should have all
> the
> > values of those keys which i pass.
> >
> > ##################
> > mydict.get('a','b','c')    ###demo for what i want
> > 'apple','boy','cat'        ### Output i want
> > #################
>
> 1. You can use a list comprehension
>
> >>> [mydict[k] for k in 'a', 'b', 'c']
> ['apple', 'boy', 'cat']
>
> 2. You can use map (for python 3.X, you need to wrap this in list(...))
>
> >>> map(mydict.__getitem__, ['a', 'b', 'c'])
> ['apple', 'boy', 'cat']
>
> 3. You can use operator.itemgetter
>
> >>> from operator import itemgetter
> >>> itemgetter('a', 'b', 'c')(mydict)
> ('apple', 'boy', 'cat')
>
> --
> Arnaud
>



-- 
Regards
Nikhil Verma
+91-958-273-3156
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