Integer as raw hex string?
MRAB
python at mrabarnett.plus.com
Mon Dec 24 13:15:51 EST 2012
On 2012-12-24 15:58, Tim Chase wrote:
> On 12/24/12 09:36, Roy Smith wrote:
>> I have an integer that I want to encode as a hex string, but I don't
>> want "0x" at the beginning, nor do I want "L" at the end if it happened
>> to be a long. The result needs to be something I can pass to int(h, 16)
>> to get back my original integer.
>>
>> The brute force way works:
>>
>> h = hex(i)
>> assert h.startswith('0x')
>> h = h[2:]
>> if h.endswith('L'):
>> h = h[:-1]
>>
>> but I'm wondering if there's some built-in call which gives me what I
>> want directly. Python 2.7.
>
> Would something like
>
> h = "%08x" % i
>
> or
>
> h = "%x" % i
>
> work for you?
>
Or:
h = "{:x}".format(i)
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