What do I do to read html files on my pc?

[Peter Otten]

mikcec82 wrote:

> Il giorno lunedì 27 agosto 2012 12:59:02 UTC+2, mikcec82 ha scritto:
>> Hallo,
>> 
>> 
>> 
>> I have an html file on my pc and I want to read it to extract some text.
>> 
>> Can you help on which libs I have to use and how can I do it?
>> 
>> 
>> 
>> thank you so much.
>> 
>> 
>> 
>> Michele
> 
> Hi Oscar,
> I tried as you said and I've developed the code as you will see.
> But, when I have a such situation in an html file, in wich there is a
> repetition of a string (XX in this case):
> CODE Target: 	        0201
> CODE Read: 	        XXXX
> CODE CHECK 	: NOT PASSED
> TEXT Target:              13
> TEXT Read: 	          XX
> TEXT CHECK 	: NOT PASSED
> CHAR Target: 	          AA
> CHAR Read: 	          XX
> CHAR CHECK 	: NOT PASSED
> 
> With this code (created starting from yours)
> 
> index = nomefile.find('XXXX')
> print 'XXXX_ found at location', index
> 
> index2 = nomefile.find('XX')
> print 'XX_ found at location', index2
> 
> found = nomefile.find('XX')
> while found > -1:
>     print "XX found at location", found
>     found = nomefile.find('XX', found+1)
> 
> I have an answer like this:
> 
> XXXX_ found at location 51315
> XX_ found at location 51315
> XX found at location 51315
> XX found at location 51316
> XX found at location 51317
> XX found at location 52321
> XX found at location 53328
> 
> I have done it to find all occurences of 'XXXX' and 'XX' strings. But, as
> you can see, the script find the occurrences of XX also at locations
> 51315, 51316 , 51317 corresponding to string XXXX.
> 
> Is there a way to search all occurences of XX avoiding XXXX location?

Remove the wrong positives afterwards:

start = nomefile.find("XX")
while start != -1:
    if nomefile[start:start+4] == "XXXX":
        start += 4
    else:
        print "XX found at location", start
        start += 3
    start = nomefile.find("XX", start)

By the way, what do you want to do if there are runs of "X" with repeats 
other than 2 or 4?