Dynamically determine base classes on instantiation

[Steven D'Aprano]

On Thu, 16 Aug 2012 10:09:08 -0700, Richard Thomas wrote:

>> a is a Foo
>> b is a Foo
>> therefore a and b are the same type
> 
> What you mean here is "a and b share a common base class".

No. I mean what I said: since a and b are both direct instances of Foo, 
not subclasses, they are both the same type, namely Foo.

"Share a common base class" is a much weaker statement:

class Foo: pass
class Bar(Foo): pass

a = Foo()
b = Bar()

Now we can see that a and b are NOT the same type, but they share a 
common base class, Foo.


-- 
Steven