save dictionary to a file without brackets.

[Tim Chase]

On 08/09/12 15:41, Roman Vashkevich wrote:
> 10.08.2012, в 0:35, Tim Chase написал(а):
>> On 08/09/12 15:22, Roman Vashkevich wrote:
>>>> {(4, 5): 1, (5, 4): 1, (4, 4): 2, (2, 3): 1, (4, 3): 2}
>>>> and i want to print to a file without the brackets comas and semicolon in order to obtain something like this?
>>>> 4 5 1
>>>> 5 4 1
>>>> 4 4 2
>>>> 2 3 1
>>>> 4 3 2
>>>
>>> for key in dict:
>>> 	print key[0], key[1], dict[key]
>>
>> This might read more cleanly with tuple unpacking:
>>
>>  for (edge1, edge2), cost in d.iteritems(): # or .items()
>>    print edge1, edge2, cost
>>
>> (I'm making the assumption that this is a edge/cost graph...use
>> appropriate names according to what they actually mean)
>
> dict.items() is a list - linear access time whereas with 'for
> key in dict:' access time is constant:
> http://python.net/~goodger/projects/pycon/2007/idiomatic/handout.html#use-in-where-possible-1

That link doesn't actually discuss dict.{iter}items()

Both are O(N) because you have to touch each item in the dict--you
can't iterate over N entries in less than O(N) time.  For small
data-sets, building the list and then iterating over it may be
faster faster; for larger data-sets, the cost of building the list
overshadows the (minor) overhead of a generator.  Either way, the
iterate-and-fetch-the-associated-value of .items() & .iteritems()
can (should?) be optimized in Python's internals to the point I
wouldn't think twice about using the more readable version.

-tkc