Zipping a dictionary whose values are lists

[Pavel Anossov]

zip(*d.values())

On 12 April 2012 20:28,  <tkpmep at gmail.com> wrote:
> I using Python 3.2 and have a dictionary
>>>> d = {0:[1,2], 1:[1,2,3], 2:[1,2,3,4]}
>
> whose values are lists I would like to zip into a list of tuples. If I explicitly write:
>>>> list(zip([1,2], [1,2,3], [1,2,3,4])
> [(1, 1, 1), (2, 2, 2)]
>
> I get exactly what I want. On the other hand, I have tried
>
>>>>list(zip(d))
> [(0,), (1,), (2,)]
>
>>>> list(zip(d.values()))
> [([1, 2],), ([1, 2, 3],), ([1, 2, 3, 4],)]
>
>>>> list(zip(d[i] for i in d))
> [([1, 2],), ([1, 2, 3],), ([1, 2, 3, 4],)]
>
>>>> list(zip(*d))
> Traceback (most recent call last):
>  File "<pyshell#48>", line 1, in <module>
>    list(zip(*d))
> TypeError: zip argument #1 must support iteration
>
> and nothing quite works. What am I doing wrong?
>
> Sincerely
>
> Thomas Philips
> --
> http://mail.python.org/mailman/listinfo/python-list



-- 
С уважением, Аносов Павел