How to filter a dictionary ?

[Shashank Singh]

On Mon, Apr 9, 2012 at 10:49 PM, Nikhil Verma <varma.nikhil22 at gmail.com>wrote:

>
> for_patient_type = {37: u'Test', 79: u'Real', 80: u'Real', 81: u'Real',
> 83: u'Real', 84: u'Real', 91: u'Real', 93: u'Real'}
>
> I want if the values are 'Real' give me the keys that have values 'Real'
> like this.
>
> {79:'Real'}
> {80:'Real'}
> {81:'Real'}
> {83:'Real'}
> {84:'Real'}
> {91:'Real'}
> {93:'Real'}
>

if you want the dict filtered

Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49)
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> for_patient_type = {37: u'Test', 79: u'Real', 80: u'Real', 81: u'Real',
83: u'Real', 84: u'Real', 91: u'Real', 93: u'Real'}
>>> dict((k, for_patient_type[k]) for k in for_patient_type if
for_patient_type[k] == 'Real')
{79: u'Real', 80: u'Real', 81: u'Real', 83: u'Real', 84: u'Real', 91:
u'Real', 93: u'Real'}
>>>

If you just want the keys

>>> [k for k in for_patient_type if for_patient_type[k] == 'Real']
[80, 81, 83, 84, 91, 93, 79]
>>>


>
> I am trying this but its giving me a generator object.
>
> In [9]: (k for k,v in for_patient_type.iteritems() if v == 'Real')
>

Iterating over a dict gives you all the keys, not the key value pairs



-- 
Regards
Shashank Singh
  http://www.flipora.com
http://r <http://www.cse.iitb.ac.in/~shashanksingh>ationalpie.wordpress.com
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