Problem using execvp

[James Housden]

On Oct 27, 11:27 am, Hans Mulder <han... at xs4all.nl> wrote:
> On 27/10/11 10:57:55, faucheuse wrote:
>
> > I'm trying to launch my python program with another process name than
> > "python.exe".
>
> Which version of Python are you using?
> Which version of which operating system?
>
> > In order to do that I'm trying to use the os.execvp function :
>
> > os.execvp("./Launch.py", ["ProcessName"])
>
> > Launch.py is the file that Launch the program and ProcessName is
> > the ... Process Name ^^
>
> > I get this error : OSError : [Errno 8] Exec format error.
>
> Maybe ./Lauch.py is not executable.....
>
> Can you run ./Launch.py from the command line?
> Does it have a valid shebang line?
> Is the 'x' bit set?
> What does "file ./Launch.py" report?
>
> > I searched and found many solutions like : os.execvp("./Launch.py",
> > ["./Launch.py","ProcessName"]), but nothing worked so far.
>
> This works for me:
>
>      os.execvp("./Launch.py", ["ProcessName"]])
>
> -- HansM

Hello,

This worked for me:
os.execvp("./Launch.py", ["python", "ProcessName"])

Best regards,
James