unpack('>f', b'\x00\x01\x00\x00')

[kuaile xu]

Hi:

I am working on a python script that parses mp4 video header. Once of
the field is a 32-bit fixed-point number.

I know that the four bytes are: 00, 01, 00, 00. I have a third party
mp4 parsing program which displays this field's value is:1.0.

However, the struct.unpack gets a value of 0.0.

Python 3.2 (r32:88445, Feb 20 2011, 21:30:00) [MSC v.1500 64 bit
(AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> from struct import *
>>> unpack('>f', b'\x00\x01\x00\x00')
(9.183549615799121e-41,)
>>>

In addition, there is another field which is a 16-bit fixed point
number. How do I unpack two bytes into a float?

Thank you very much,