Converting a set into list

[SigmundV]

I think the OP wants to find the intersection of two lists.
list(set(list1) & set(list2)) is indeed one way to achieve this. [i
for i in list1 if i in list2] is another one.

Sigmund

On May 15, 4:11 am, Chris Torek <nos... at torek.net> wrote:
> In article <871v00j2bh.... at benfinney.id.au>
> Ben Finney  <ben+pyt... at benfinney.id.au> wrote:
>
> >As pointed out: you already know how to create a set from an object;
> >creating a list from an object is very similar:
>
> >    list(set(aa))
>
> >But why are you doing that? What are you trying to achieve?
>
> I have no idea why someone *else* is doing that, but I have used
> this very expression to unique-ize a list:
>
>     >>> x = [3, 1, 4, 1, 5, 9, 2, 6]
>     >>> x
>     [3, 1, 4, 1, 5, 9, 2, 6]
>     >>> list(set(x))
>     [1, 2, 3, 4, 5, 6, 9]
>     >>>
>
> Of course, this trick only works if all the list elements are
> hashable.
>
> This might not be the best example since the result is sorted
> "by accident", while other list(set(...)) results are not.  Add
> sorted() or .sort() if needed:
>
>     >>> x = ['three', 'one', 'four', 'one', 'five']
>     >>> x
>     ['three', 'one', 'four', 'one', 'five']
>     >>> list(set(x))
>     ['four', 'five', 'three', 'one']
>     >>> sorted(list(set(x)))
>     ['five', 'four', 'one', 'three']
>     >>>
> --
> In-Real-Life: Chris Torek, Wind River Systems
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