Convert '165.0' to int

[Frank Millman]

On Jul 24, 9:34 am, Steven D'Aprano <steve
+comp.lang.pyt... at pearwood.info> wrote:
> Frank Millman wrote:
> > If I really wanted to be 100% safe, how about this -
>
> >     def get_int(s):
> >         if '.' in s:
> >             num, dec = s.split('.', 1)
> >             if dec != '':
> >                 if int(dec) != 0:
> >                     raise ValueError('Invalid literal for int')
> >             return int(num)
> >         return int(s)
>
> Consider what happens if you pass s = "42.-0".
>

Grrrr!

Ok, what if I change
    if int(dec) != 0:
to
    if [_ for _ in list(dec) if _ != '0']:

If I do this, I can get rid of the previous line -
    if dec != ''

Am I getting closer?

Frank