Understanding def foo(*args)

[Mel]

sl33k_ wrote:

> Hi,
> 
> I am struggling to grasp this concept about def foo(*args). Also, what
> is def bar(*args, *kwargs)?
> 
> Isnt it like self must be the first parameter to the method/function?
> If not what are the exceptions?
> 
> Also, can the terms method and function be used interchangeably?
> 
> TIA

Try

def foo (*args):
    print 'foo args:', repr (args)

foo (1, 2, 3, 4)

def bar (*args, **kwargs):
    print 'bar args:', args
    print 'bar kwargs:', kwargs

bar (1, 2, 3, 4)
bar (1, 2, 3, baz=6, boz=None)


	Mel.