compute the double square...... :(

[Owen]

On Jan 9, 6:14 pm, Gary Herron <gher... at islandtraining.com> wrote:
> On 01/08/2011 10:10 PM, aregee wrote:
>
> > Double Squares
> > A double-square number is an integer X which can be expressed as the
> > sum of two perfect squares. For example, 10 is a double-square because
> > 10 = 32 + 12. Your task in this problem is, given X, determine the
> > number of ways in which it can be written as the sum of two squares.
> > For example, 10 can only be written as 32 + 12 (we don't count 12 + 32
> > as being different). On the other hand, 25 can be written as 52 + 02
> > or as 42 + 32.
>
> Huh?  In what number system does  10 = 32 + 12?
> And how do either 32 or 12 qualify as perfect squares?
>
> Gary Herron
>
>
>
>
>
>
>
> > Input
> > You should first read an integer N, the number of test cases. The next
> > N lines will contain N values of X.
> > Constraints
> > 0 ≤ X ≤ 2147483647
> > 1 ≤ N ≤ 100
> > Output
> > For each value of X, you should output the number of ways to write X
> > as the sum of two square
>
> > Is the code mention below solution to this question ???? what is the
> > fault...
> > Error :
> > aregee at aregee-laptop:~/Desktop$ python pie.py
> > enter a number::10
> > pie.py:3: Deprecation Warning: integer argument expected, got float
> >    for b in range(0,(x**0.5)/2):
>
> > #Double square....
>
> > x = input("enter a number::")
> > for b in range(0,(x**0.5)/2):
> >        a = (x-(b**2))**0.5
> > try:
> >        a = int(a)
> > except:
> >        print("not an integer")
> >        exit(1)
>
> >        count = 0;
> >        count = count + 1;
> > if (x == a**2 + b**2):
>
> >        print "double square"



Well that he means 3(squared)+1(squared) [3 superscript 2 etc]

Owen