testing if a list contains a sublist

[Roy Smith]

In article <mailman.27.1313450819.27778.python-list at python.org>,
 Johannes <dajo.mail at web.de> wrote:

> hi list,
> what is the best way to check if a given list (lets call it l1) is
> totally contained in a second list (l2)?
> 
> for example:
> l1 = [1,2], l2 = [1,2,3,4,5] -> l1 is contained in l2
> l1 = [1,2,2,], l2 = [1,2,3,4,5] -> l1 is not contained in l2
> l1 = [1,2,3], l2 = [1,3,5,7] -> l1 is not contained in l2
> 
> my problem is the second example, which makes it impossible to work with
> sets insteads of lists. But something like set.issubset for lists would
> be nice.
> 
> greatz Johannes

import re

def sublist(l1, l2):
    s1 = ''.join(map(str, l1))
    s2 = ''.join(map(str, l2))
    return re.search(s1, s2)

assert sublist([1,2], [1,2,3,4,5])
assert not sublist ([1,2,2], [1,2,3,4,5])
assert not sublist([1,2,3], [1,3,5,7])


(running and ducking)