listening socket

cerr ron.eggler at gmail.com
Wed Sep 8 13:11:16 EDT 2010


On Sep 8, 10:06 am, Benjamin Kaplan <benjamin.kap... at case.edu> wrote:
> On Wed, Sep 8, 2010 at 12:59 PM, cerr <ron.egg... at gmail.com> wrote:
> > Hi,
>
> > I'm trying to create a listening socket connection on port 1514.
> > I tried to follow the documentation at:
> >http://docs.python.org/release/2.5.2/lib/socket-example.html
> > and came up with following lines:
> > import socket
>
> > host = ''                 # Symbolic name meaning all available
> > interfaces
> > port = 1514               # Arbitrary non-privileged port
> > s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
> > s.bind((host, port))
> > s.listen(1)
> > conn, addr = s.accept()
> > print 'Connected by', addr
> > while 1:
> >    data = conn.recv(1024)
> >    if not data: break
> >    conn.send(data)
> > conn.close()
> > but that is not working, i'm getting this:
> > import: unable to open X server `' @ error/import.c/ImportImageCommand/
> > 362.
> > ./sockettest.py: line 4: host: command not found
> > ./sockettest.py: line 5: port: command not found
> > ./sockettest.py: line 6: syntax error near unexpected token `('
> > ./sockettest.py: line 6: `s = socket.socket(socket.AF_INET,
> > socket.SOCK_STREAM)'
>
> > now why would it try to open an x server??? :o
> > --
>
> Because it's not executing it as a Python program. It's trying to
> execute it as a shell script. If you want to run a script as a Python
> program, either call the interpreter directly
> python sockettest.py
>
> or include a Shebang line as the first line of the file that tells the
> computer what interpreter to use
> #!/usr/bin/env python
>
> The file extension itself is meaningless to a Unix shell- it's just a
> part of the file name.

hoops right... heh, thanks... :$ clearly doing too many things at the
same time...



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