compare dictionaries

[Baba]

On 7 sep, 22:37, MRAB <pyt... at mrabarnett.plus.com> wrote:
> On 07/09/2010 21:06, Paul Rubin wrote:
>
> > Baba<raoul... at gmail.com>  writes:
> >> word= 'even'
> >> dict2 = {'i': 1, 'n': 1, 'e': 1, 'l': 2, 'v': 2}
>
> >> i want to know if word is entirely composed of letters in dict2
>
> > set(word)<= set(dict2.keys())
>
> Do the numbers in dict2 represent the maximum number of times that the
> letter can be used?
>
> If yes, then build a similar dict for the word with the number of times
> that each letter occurs in the word and then check for every pair in
> the dict whether the key (ie, letter) occurs in dict2 and that the
> value (number of occurrences) isn't too many.

Hi MRAB

Thanks for the hint. In my case i need to do the opposite: the number
of times that each letter ocurs in the word needs to be smaller or
equal to the number of times it apears in dict2. That way i am
guaranteed that word is entirely made up of elements of dict2.

Your hint pointed me in the right direction.

        for k in word.keys():
            if k not in hand:
                return False
            elif k in hand:
              if word[k] > hand[k]:
                  return False
        return True

Baba