another way to sort like l.sort(key=lambda x:(x[0][0], -x[1][0]))

[sajuptpm]

On Sep 7, 7:03 pm, Peter Otten <__pete... at web.de> wrote:
> sajuptpm wrote:
> > i need to implement  l.sort(key=lambda x:(x[0][0], -x[1][0])) in
> > another way .I want to know what the modification needed in the 'if'
> > check to sort this list of tuples in k[0][0] ascending and k[0][1]
> > descending.
>
> It seems you are not getting any closer to your goal. Perhaps it would help
> if you could explain that goal clearly rather than describing the means you
> are employing to achieve it.
>
> > I have a list of tuples.
>
> > l = [((30,50),(70)), ((50,20),(20))]
>
> By the way, (42) is not a tuple, it's an integer. To turn it into a 1-tuple
> you have to add a ',':
>
> >>> (42)
> 42
> >>> (42,)
> (42,)
> >>> 42,
>
> (42,)
>
> Peter


I have a list of tuples.

l = [((30,50),(70,)), ((50,20),(20,))]

for i in range(10):
        k = ((i+30,i+50),(i+70))#suppose creating new tuple in each
iteration
using some random value and in sert it into list.

        flag=True
        for i, v in enumerate(l):
        if v >= k:
                l.insert(i,k)
                flag = False
                break
        if flag:
        l.append(k)

This code will give a list of tuples sorted in asc order.
I need to change this code to sort this list by k[0][0] ascending and
k[0][1] descending.
What are the modifications needed in this code.
I dont want to user sort() method of list.

i need to implement  l.sort(key=lambda x:(x[0][0], -x[1][0])) in
another way .I want to know what the modification needed in the 'if'
check to sort this list of tuples in k[0][0] ascending and k[0][1]
descending.