function that counts...

[superpollo]

Jerry Hill ha scritto:
> On Wed, May 19, 2010 at 4:25 PM, superpollo <utente at esempio.net> wrote:
>> Jerry Hill ha scritto:
>>>        sumofdigits = sum(int(char) for char in str(testval))
>> this line gives me this:
>>
>> TypeError: 'int' object is not callable
>>
>> is it some new feature in >2.5 ?
> 
> No, sum() has been a builtin since Python 2.3.  Based on your first
> post, you have probably shadowed the builtin "sum" function by
> assigning an integer to a variable named "sum".

o my... thanks!

In [266]: del(sum)

In [267]: def prttn2(m, n):
     """How many positive integers less than n have digits that sum up 
to m"""
     total = 0
     for testval in range(n):
         sumofdigits = sum(int(char) for char in str(testval))
         if sumofdigits == m:
             total += 1
     return total
    .....:

In [275]: def prttn3(m, n):
     return sum(1 for x in range(n) if sum(map(int, str(x))) == m)
    .....:

In [277]: prttn(25, 10000)
Out[277]: 348

In [278]: prttn2(25, 10000)
Out[278]: 348

In [279]: prttn3(25, 10000)
Out[279]: 348

ok, bye!