itertools: problem with nested groupby, list()
Ulrich Eckhardt
eckhardt at satorlaser.com
Tue May 4 08:09:41 EDT 2010
Nico Schlömer wrote:
> So when I go like
>
> for item in list:
> item[1].sort()
>
> I actually modify *list*? I didn't realize that; I thought it'd just
> be a copy of it.
No, I misunderstood your code there. Modifying the objects inside the list
is fine, but I don't thing you do that, provided the items in the list
don't contain references to the list itself.
Good luck!
Uli
--
Sator Laser GmbH
Geschäftsführer: Thorsten Föcking, Amtsgericht Hamburg HR B62 932
More information about the Python-list
mailing list