(a==b) ? 'Yes' : 'No'

Peter Otten __peter__ at web.de
Wed Mar 31 03:57:51 EDT 2010


Pierre Quentel wrote:

> I'm surprised nobody proposed a solution with itertools ;-)

next(itertools.takewhile(lambda _: a == b, ["yes"]), "no")

You spoke to soon :)

Peter



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