passing environment variable path to open command

[Jean-Michel Pichavant]

Mahmood Naderan wrote:
>
> Hi,
> I am new to python so my question may be very basic.
> Suppose I have a file (sc_1.sh) which the path to that file is in 
> system path:
>
> SOMETHING=/home/mahmood/scripts
>
>  
>
> Now I want to open that file with respect to the environment variable:
>    import os
>    env = os.getenv("SOMETHING")
>    print env
>
>    infile = open("env/sc_1.sh","r")
>
>  
>
> But here is the error I get:
> /home/mahmood/scripts
> Traceback (most recent call last):
>   File "test.py", line 7, in <module>
>     infile = open("env/sc_1.sh","r")
> IOError: [Errno 2] No such file or directory: 'env/sc_1.sh'
>
>  
>
> How can I use such variable in open file command?
>
> Thanks,
>  
>
> *// Naderan *Mahmood;*
>
import os

infile = open(os.path.join(env, 'sc_1.sh'),"r")

JM