Normalizing A Vector

[Thomas Jollans]

On 07/31/2010 12:15 PM, Lawrence D'Oliveiro wrote:
>reduce(lambda a, b : a + b, (y * y for y in V), 0))
> 

This is a lot more verbose than it has to be, and probably slower too.

firstly:

(lambda a,b: a+b) is equivalent to operator.add.

==>
reduce(operator.add, (y*y for y in V), 0)

However - reduce with operator.add ? we have a special name for this:

==>
sum(y*y for y in V)