Function closure inconsistency

[Terry Reedy]

On 7/23/2010 2:30 PM, SeanMon wrote:
> I was playing around with Python functions returning functions and the
> scope rules for variables, and encountered this weird behavior that I
> can't figure out.
>
> Why does f1() leave x unbound, but f2() does not?
>
> def f1():
>      x = 0
>      def g():
In 3.x, add
            nonlocal x
>          x += 1
>          return x
>      return g1
You meant g

def f1():
      x = 0
      def g():
           nonlocal x
           x += 1
           return x
      return g
f=f1()
print(f())
print(f())
print(f())
print(f())

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-- 
Terry Jan Reedy