Python dos2unix one liner

[Steven D'Aprano]

On Sat, 27 Feb 2010 19:37:50 -0800, staticd wrote:

>> >Amusing how long those Python toes can be. In several replies I have
>> >noticed (often clueless) opinions on Perl. When do people learn that a
>> >language is just a tool to do a job?
>>
>> When do people learn that language makes a difference?  I used to be a
>> Perl programmer; these days, you'd have to triple my not-small salary
>> to get me to even think about programming in Perl.
> 
> dude, you nailed it.  many times, if not _always_, the correct output is
> important.  the method used to produce the output is irrelevant.

Oh really?

Then by that logic, you would consider that these two functions are both 
equally good. Forget readability, forget maintainability, forget 
efficiency, we have no reason for preferring one over the other since the 
method is irrelevant.


def greet1(name):
    """Print 'Hello <name>' for any name."""
    print "Hello", name


def greet2(name):
    """Print 'Hello <name>' for any name."""
    count = 0
    for i in range(0, ("Hello", name).__len__(), 1):
        word = ("Hello", name).__getitem__(i)
        for i in range(0, word[:].__len__(), 1):
            c = word.__getitem__(i)
            import sys
            import string
            empty = ''
            maketrans = getattr.__call__(string, 'maketrans')
            chars = maketrans.__call__(empty, empty)
            stdout = getattr.__call__(sys, 'stdout')
            write = getattr.__call__(stdout, 'write')
            write.__call__(c)
        count = count.__add__(1)
        import operator
        eq = getattr.__call__(operator, 'eq')
        ne = getattr.__call__(operator, 'ne')
        if eq.__call__(count, 2):
            pass
        elif not ne.__call__(count, 2):
            continue
        write.__call__(chr.__call__(32))
    write.__call__(chr.__call__(10))
    return None



There ought to be some kind of competition for the least efficient 
solution to programming problems-ly y'rs,


-- 
Steven