assigning variables from list data

[Benjamin Kaplan]

On Thu, Aug 5, 2010 at 7:26 AM, Chris Hare <chare at labr.net> wrote:
>
> I have a database query result (see code below).  In PHP, I would have said
>
> list(var1,var2,var) = $result
>
> and each element in the list would be assigned to each of the named variables.  I have my data coming out of the database, and I can see it is a list.  so my question is, instead of having to do the variable assignment as I have it here, is there a way more like PHP or am I stuck with it?
>
> import sqlite3 as sqlite
>
> try:
>        print "connecting to disk db ..."
>        conn = sqlite.connect("netcomm.db")
> except:
>        print "oops"
>
> print "retrieving data"
> cursor = conn.cursor()
> cursor.execute('select * from net where NetNumber > 0')
> list = cursor.fetchone()
> print list
> print len(list)
> for item in list:
>    print item
> netNumber = list[0]
> netType = list[1]
> netConditions = list[2]
> netStartLocal = list[3]
> NCS = list[4]
> NCS1 = list[5]
> RADAR = list[6]
> NetFreq = list[7]
> Repeater = list[8]
> Notes = list[9]
> --

netNumber, netType, netConditions, netStartLocal, NCS, NCS1, RADAR,
NetFreq, Repeater, Notes = list

by the way, don't call the list "list". It will hide the built-in with
the same name.

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