Comparing lists

Francesco Bochicchio bieffe62 at gmail.com
Mon Aug 16 06:46:07 EDT 2010


Hi all,

anybody can point me to a description of how the default comparison of
list objects (or other iterables) works?

Apparently l1 <  l2 is equivalent to  all ( x < y  for  x,y in
zip( l1, l2) ), has is shown in the following tests, but I can't find
it described anywhere:

>>> [1,2,3] < [1,3,2]
True
>>> [1,2,3] < [1,2,4]
True
>>> [1,2,3] < [2,2,3]
True
>>> [1,2,3] < [0,1,3]
False
>>> [1,2,3] < [0,2,3]
False
>>> [1,2,3] < [1,1,3]
False
>>> [1,2,3] < [1,2,2]
False


Ciao
---
FB



More information about the Python-list mailing list