Regex trouble
Rhodri James
rhodri at wildebst.demon.co.uk
Thu Sep 24 18:31:39 EDT 2009
On Thu, 24 Sep 2009 19:45:37 +0100, Simon Forman <sajmikins at gmail.com>
wrote:
> FWIW this problem is too simple (IMHO) for regular expressions.
> Simply carve off the first three digits and check against sets of the
> prefixes you're interested in:
>
>
> #any number starting with these prefixes is not long distance
> local_prefixes = set(['832', '877', '888', '713', '866', '011', '001',
> '281', '800'])
>
> long_distance= {}
> for key1, value1 in x.iteritems():
> if key1 == 'dest':
> if value1[:3] not in local_prefixes:
> long_distance[key1] = value1
You need to allow for the potential leading 1, which can be done with
a bit of straightforward string slicing but still puts REs more
sensibly in the running.
--
Rhodri James *-* Wildebeest Herder to the Masses
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