Remove empty strings from list

[Join hack]

good solution ,thanks~!

2009/9/15 Steven D'Aprano <steven at remove.this.cybersource.com.au>

> On Mon, 14 Sep 2009 18:55:13 -0700, Chris Rebert wrote:
>
> > On Mon, Sep 14, 2009 at 6:49 PM, Helvin <helvinlui at gmail.com> wrote:
> ...
> > > I have looked at documentation, and how strings and lists work, but I
> > > cannot understand the behaviour of the following:
> ...
> > >                        for item in list:
> > >                                if item is ' ':
> > >                                        print 'discard these: ',item
> > >                                        index = list.index(item)
> > >                                        del list[index]
>
> ...
>
> > Moral: Don't modify a list while iterating over it. Use the loop to
> > create a separate, new list from the old one instead.
>
>
> This doesn't just apply to Python, it is good advice in every language
> I'm familiar with. At the very least, if you have to modify over a list
> in place and you are deleting or inserting items, work *backwards*:
>
> for i in xrange(len(alist), -1, -1):
>    item = alist[i]
>    if item == 'delete me':
>        del alist[i]
>
>
> This is almost never the right solution in Python, but as a general
> technique, it works in all sorts of situations. (E.g. when varnishing a
> floor, don't start at the doorway and varnish towards the end of the
> room, because you'll be walking all over the fresh varnish. Do it the
> other way, starting at the end of the room, and work backwards towards
> the door.)
>
> In Python, the right solution is almost always to make a new copy of the
> list. Here are three ways to do that:
>
>
> newlist = []
> for item in alist:
>    if item != 'delete me':
>         newlist.append(item)
>
>
> newlist = [item for item in alist if item != 'delete me']
>
> newlist = filter(lambda item: item != 'delete me', alist)
>
>
>
> Once you have newlist, you can then rebind it to alist:
>
> alist = newlist
>
> or you can replace the contents of alist with the contents of newlist:
>
> alist[:] = newlist
>
>
> The two have a subtle difference in behavior that may not be apparent
> unless you have multiple names bound to alist.
>
>
>
> --
> Steven
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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