Extracting patterns after matching a regex

[Mart.]

On Sep 8, 2:15 pm, MRAB <pyt... at mrabarnett.plus.com> wrote:
> Martin wrote:
> > Hi,
>
> > I need to extract a string after a matching a regular expression. For
> > example I have the string...
>
> > s = "FTPHOST: e4ftl01u.ecs.nasa.gov"
>
> > and once I match "FTPHOST" I would like to extract
> > "e4ftl01u.ecs.nasa.gov". I am not sure as to the best approach to the
> > problem, I had been trying to match the string using something like
> > this:
>
> > m = re.findall(r"FTPHOST", s)
>
> > But I couldn't then work out how to return the "e4ftl01u.ecs.nasa.gov"
> > part. Perhaps I need to find the string and then split it? I had some
> > help with a similar problem, but now I don't seem to be able to
> > transfer that to this problem!
>
> > Thanks in advance for the help,
>
> m = re.search(r"FTPHOST: (.*)", s)
> print m.group(1)

so the .* means to match everything after the regex? That doesn't help
in this case as the string is placed amongst others for example.

MEDIATYPE: FtpPull\r\n', 'MEDIAFORMAT: FILEFORMAT\r\n', 'FTPHOST:
e4ftl01u.ecs.nasa.gov\r\n', 'FTPDIR: /PullDir/0301872638CySfQB\r\n',
'Ftp Pull Download Links: \r\n',